13x^2+24x-884=0

Solution for 13x^2+24x-884=0 equation:

13x^2+24x-884=0

a = 13; b = 24; c = -884;
Δ = b2-4ac
Δ = 242-4·13·(-884)
Δ = 46544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{46544}=\sqrt{16*2909}=\sqrt{16}*\sqrt{2909}=4\sqrt{2909}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{2909}}{2*13}=\frac{-24-4\sqrt{2909}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{2909}}{2*13}=\frac{-24+4\sqrt{2909}}{26}
$